链表中重复元素的删除

#include <stdio.h>
#include <stdlib.h>
#include <iostream>
using namespace std;
struct node
{
    int data;
    struct node *next;
};
struct node *creat(int n)
{
    struct node *head,*p;
    head=(struct node *)malloc(sizeof(struct node));
    head->next=NULL;
    for(int i=0;i<n;i++)
    {
        p=(struct node *)malloc(sizeof(struct node ));
        scanf("%d",&p->data);
        p->next=head->next;
        head->next=p;
    }
    return head;
};
void show (struct node *head)
{
    struct node *p;
    p=head->next;
    while(p)
    {
        if(!p->next)
        {
            printf("%d\n",p->data);
        }
        else
        {
            printf("%d ",p->data);
        }
        p=p->next;
    }
}
void del(struct node *&head,int &n)
{
    struct node *q,*p,*t;
    p=head->next;
    while(p)
    {
        t=q;          //上t在p的位置上
        q=p->next;    //让q代表遍历的指针
        while(q)
        {
            if(q->data==p->data)  //当查找到重复的元素的时候
            {
                t->next=p->next;
                n--;
                p=p->next;
            }
            else
            {
                t=t->next;
                p=p->next;
            }
        }
        q=q->next;
    }
}
int main()
{
    struct node *head;
    int n;
    scanf("%d",&n);
    head=creat(n);
    printf("%d\n",n);
    show(head);
    del(head,n);
    printf("%d\n",n);
    show(head);
}